What is a Super Heinz bet
Super Heinz bets fall into the category of “Full cover bets” as it offers the punter full coverage on all combinations of multiples. A Heinz consists of 7 selections that form 120 separate bets. 21 doubles, 35 trebles 35 fourfold accumulators, 21 fivefold accumulators, 7 six fold accumulators and a seven fold accumulator. In order for the bet to have a return at least 2 selections must win.
Bookies that offer Super Heinz betting
Big multiple bets are a bookies bread and butter, they love punters that place these bets. As more often than not you are multiplying together odds in their favour, which gives them a bigger edge.
We are hoping if you are placing this type of bet either you have many selections you think the bookmakers has got wrong (and therefore multiplying value in your favour) or you are just having a fun punt in the hope of winning big.
Whatever the reason for placing a Super Heinz bet we would recommend the following bookies as a good starting point for signing up with trustworthy bookies.
Super Heinz calculations
You might be thinking there’s no need to learn this, I trust the bookmaker I bet with. Well yes most bookmakers are very trustworthy and the industry is very well regulated, so you can be sure if any mistakes are made they will be honest mistakes. This skill is more for the odd occasion that they do make a mistake or for the time you’re down the pool hall watching the final leg of your Super Heinz come in on their big screen TV. If you could work it out yourself easily you can decide whether to leave collecting your winning until the next day and stay playing pool with your mates, or whether you should run down to the bookie before they close to collect the small fortune you just won and have a big night out.
So what knowledge do you need to make this decision? At the very minimum all you need is a simple equation, but normally you will need the equation and the use of a calculator (I know not many people will be walking around with a hand held calculator but the basic calculator on your phone will be more than sufficient). For some it will be beneficial to see how the equation for a super Heinz was derived and for these people we’ll show the basics of how this was achieved.
Let’s look at a very simple equation and then multiple out the brackets
(A + 1)(B + 1)(C + 1) = ABC + AB + AC + BC + A + B + C + 1
The observant amongst you will see that once the equation that has been simplified has a resemblance of a long winded Trixie bet settlement equation. One treble and three doubles. But it has elements that aren’t needed, the singles and +1. So if the original equation had these subtracted from it then it would become the equation needed to work out a Trixie bet. Knowing this it is then easy to see that if this equation is extended to six variables instead of three (with the subtraction included) we’ll have the equation for Super Heinz settlement.
(A + 1)(B + 1)(C + 1)(D + 1)(E + 1)(F + 1) – (A + B + C + D + E + F + 1)
You would be excused from thinking that’s a lot to remember for calculating just one type of combination bet, but this equation with more or less variables is used for all full cover bets, such as a Yankee, a Canadian bet and a Goliath bet. It also a variation on the equation for full cover bets with singles, such as a Lucky 15, a Lucky 31 and a Lucky 63. In fact for these the equation is even easier as the subtraction section of the equations is not needed.
Super Heinz examples
For those that did well at maths in their education the equation from the calculation section will be all that is needed to understand how to calculate a super Heinz. But as not everyone is lucky enough to have a mathematical brain this example should clear up any confusion. If not at least you have found a website that offers a free independent betting calculator.
You have a £0.50 unit stake super Heinz with all selections winning. The odds are 2, 3, 3, 1.5, 4 and 5. Add these odds to the equation and you get
(2 + 1)(3 + 1)(3 + 1)(1.5 + 1)(4 + 1)(5 + 1) – (2 + 3 + 3 + 1.5 + 4 + 5 + 1)
3 x 4 x 4 x 2.5 x 5 x 6 – 19.5 = 3580.5
As easy as that you have worked out all 120 accumulators of a super Heinz bet and if you had placed this bet you’d be delighted to know you have just won £3580.5 x £0.5 = £1790.25. The multiplying of 0.5 is because that is the unit stake you placed on this bet.